Measusrement
A vernier caliper has $10$ vernier divisions equal to $9$ main scale divisions. Vernier constant is:
A) $1\ \text{MSD}$
B) $0.1\ \text{mm}$
C) $0.01\ \text{cm}$
D) $0.1\ \text{cm}$
If least count is $0.01\ \text{cm}$ and zero error is $-0.02\ \text{cm}$, the corrected length for $2.50\ \text{cm}$ is:
A) $2.48\ \text{cm}$
B) $2.52\ \text{cm}$
C) $2.50\ \text{cm}$
D) $2.49\ \text{cm}$
In screw gauge, pitch is $0.5\ \text{mm}$ and $50$ divisions on circular scale. Least count is:
A) $0.01\ \text{mm}$
B) $0.1\ \text{mm}$
C) $0.5\ \text{mm}$
D) $0.02\ \text{mm}$
If screw gauge has positive zero error of $+2$ divisions (LC $=0.01\ \text{mm}$), the corrected reading $= $
A) observed $-0.02\ \text{mm}$
B) observed $+0.02\ \text{mm}$
C) observed $+0.2\ \text{mm}$
D) no change
Vernier constant $=$
A) value of 1 main scale division
B) value of 1 vernier division
C) difference between 1 MSD and 1 VD
D) sum of 1 MSD and 1 VD
Micrometer measures:
A) time intervals
B) small lengths/thickness
C) mass
D) temperature
If $x=10\pm0.2$, the fractional uncertainty is:
A) $0.02$
B) $2$
C) $20\%$
D) $0.2$
Register or Login for comments
Comments: