Thermodynamic
Heat capacity of a body is
A) heat per mole
B) heat required per unit temperature rise
C) m/c
D) c/m
Mixture problems use principle
A) energy not conserved
B) heat lost by hot = heat gained by cold
C) masses equal
D) volumes equal
Numerical: 0.4 kg copper (390) at 200°C into 0.5 kg water at 20°C. Final T˜
A) 28°C
B) 34°C
C) 40°C
D) 50°C
Numerical: 1.0 kg water at 100°C converted to steam (Lv=2.26 MJ/kg). Heat˜
A) 2.26 kJ
B) 22.6 kJ
C) 226 kJ
D) 2.26 MJ
Work at constant pressure is
A) W = P?V
B) W = ?U
C) W = 0
D) W = nR?T
For an ideal gas, ?U equals
A) nCv?T
B) nCp?T
C) nR ln(V2/V1)
D) P?V
Numerical: 2.0 mol ideal monoatomic gas heated at constant V by 50 K. ?U˜
A) 2×(3/2)R×50
B) 2×(5/2)R×50
C) 2×R×50
D) 0
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